{3}HoDoKu Death Blossom

Stem Pink : {0}

ALSs:
{2}

Elims Red : {1}
No matter the value of the stem cell {0}, one of the Almost Locked Sets (ALS) becomes a Locked Set (LS), and ALL of these Locked Sets preclude the red/s; therefore we can eliminate the red/s, without needing to know which ALS becomes an LS.

Here's an explanation from https://www.sudopedia.org/wiki/Solving_Technique

A Death Blossom consists of a "stem" cell and an Almost Locked Set (or ALS) for each of the stem cell's candidates. The ALS associated with a particular candidate of the stem cell has that value as one of its own candidates, and within the ALS, every cell that has the value as a candidate can see the stem cell. The ALSes can't overlap; i.e., no cell can belong to more than one ALS. Also, there must be at least one value that is a candidate of every ALS, but is not a candidate of the stem cell (these are the eliminatable value/s (1)).

Once we've found a Death Blossom, if an outside cell that doesn't belong to one of the ALSes (and isn't the stem cell) can see every cell in each ALS that has that value as a candidate, and the value isn't a candidate of the stem cell, then that value can be eliminated from the outside cell.

(1) I've since discovered that the-value-to-eliminate must be common to all ALSs in the DeathBlossom, and is not a potential value of the stem cell; which makes sense: the main point is one of the ALSs becomes an LS, so all ALSs must share that value (not in stem) to preclude it from the other cell/s.

It's also worth noting that there's nothing stopping multiple values being eliminated by a Death Blossom, but it's rarer than rocking horse s__t.