{4}

The {0} cells {1} are the only possible positions of the {0} values {2} in the {3}. Because the number of cells equals the number of values, these {0} cells must contain these {0} values, in any order.

Hence other values can be removed from these cells. It follows that cell {5} is the only remaining possible position of the value {6} in the {3}.

Therefore we can remove {7}, and subsequently set {5} to {6}.

Explanation

Note that "Direct" sets are just an agglomeration of two distinct hints. It's just nice to see them both as one hint, and so it is, that's all.