{4}

The only potential values for the {0} cells {1} of the {3} are the {0} values {2}. Because the number of potential values matches the number of cells, these {0} values must be located in these {0} cells, in any order.

Hence other possible positions of these values can be removed from the {3}, which leaves cell {5} with the only remaining potential value of {6}.

Therefore we can remove{7}, and subsequently set {5} to {6}.

Explanation

Note that "Direct" sets are just an agglomeration of two distinct hints. It's just nice to see them both as one hint, and so it is, that's all.